3.23.89 \(\int \frac {(1-2 x)^{5/2}}{\sqrt {3+5 x}} \, dx\)

Optimal. Leaf size=94 \[ \frac {1}{15} \sqrt {5 x+3} (1-2 x)^{5/2}+\frac {11}{60} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {121}{200} \sqrt {5 x+3} \sqrt {1-2 x}+\frac {1331 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{200 \sqrt {10}} \]

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Rubi [A]  time = 0.02, antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {50, 54, 216} \begin {gather*} \frac {1}{15} \sqrt {5 x+3} (1-2 x)^{5/2}+\frac {11}{60} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {121}{200} \sqrt {5 x+3} \sqrt {1-2 x}+\frac {1331 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{200 \sqrt {10}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^(5/2)/Sqrt[3 + 5*x],x]

[Out]

(121*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/200 + (11*(1 - 2*x)^(3/2)*Sqrt[3 + 5*x])/60 + ((1 - 2*x)^(5/2)*Sqrt[3 + 5*x]
)/15 + (1331*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(200*Sqrt[10])

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2}}{\sqrt {3+5 x}} \, dx &=\frac {1}{15} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {11}{6} \int \frac {(1-2 x)^{3/2}}{\sqrt {3+5 x}} \, dx\\ &=\frac {11}{60} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {1}{15} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {121}{40} \int \frac {\sqrt {1-2 x}}{\sqrt {3+5 x}} \, dx\\ &=\frac {121}{200} \sqrt {1-2 x} \sqrt {3+5 x}+\frac {11}{60} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {1}{15} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {1331}{400} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=\frac {121}{200} \sqrt {1-2 x} \sqrt {3+5 x}+\frac {11}{60} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {1}{15} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {1331 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{200 \sqrt {5}}\\ &=\frac {121}{200} \sqrt {1-2 x} \sqrt {3+5 x}+\frac {11}{60} (1-2 x)^{3/2} \sqrt {3+5 x}+\frac {1}{15} (1-2 x)^{5/2} \sqrt {3+5 x}+\frac {1331 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{200 \sqrt {10}}\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 69, normalized size = 0.73 \begin {gather*} \frac {10 \sqrt {5 x+3} \left (-320 x^3+920 x^2-1406 x+513\right )+3993 \sqrt {20 x-10} \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )}{6000 \sqrt {1-2 x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)^(5/2)/Sqrt[3 + 5*x],x]

[Out]

(10*Sqrt[3 + 5*x]*(513 - 1406*x + 920*x^2 - 320*x^3) + 3993*Sqrt[-10 + 20*x]*ArcSinh[Sqrt[5/11]*Sqrt[-1 + 2*x]
])/(6000*Sqrt[1 - 2*x])

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IntegrateAlgebraic [A]  time = 0.16, size = 109, normalized size = 1.16 \begin {gather*} \frac {1331 \sqrt {1-2 x} \left (\frac {165 (1-2 x)^2}{(5 x+3)^2}+\frac {80 (1-2 x)}{5 x+3}+12\right )}{600 \sqrt {5 x+3} \left (\frac {5 (1-2 x)}{5 x+3}+2\right )^3}-\frac {1331 \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}} \sqrt {1-2 x}}{\sqrt {5 x+3}}\right )}{200 \sqrt {10}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 - 2*x)^(5/2)/Sqrt[3 + 5*x],x]

[Out]

(1331*Sqrt[1 - 2*x]*(12 + (165*(1 - 2*x)^2)/(3 + 5*x)^2 + (80*(1 - 2*x))/(3 + 5*x)))/(600*Sqrt[3 + 5*x]*(2 + (
5*(1 - 2*x))/(3 + 5*x))^3) - (1331*ArcTan[(Sqrt[5/2]*Sqrt[1 - 2*x])/Sqrt[3 + 5*x]])/(200*Sqrt[10])

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fricas [A]  time = 1.36, size = 67, normalized size = 0.71 \begin {gather*} \frac {1}{600} \, {\left (160 \, x^{2} - 380 \, x + 513\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {1331}{4000} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="fricas")

[Out]

1/600*(160*x^2 - 380*x + 513)*sqrt(5*x + 3)*sqrt(-2*x + 1) - 1331/4000*sqrt(10)*arctan(1/20*sqrt(10)*(20*x + 1
)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3))

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giac [B]  time = 1.35, size = 140, normalized size = 1.49 \begin {gather*} \frac {1}{30000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (40 \, x - 59\right )} {\left (5 \, x + 3\right )} + 1293\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 4785 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} - \frac {1}{500} \, \sqrt {5} {\left (2 \, {\left (20 \, x - 23\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 143 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {1}{50} \, \sqrt {5} {\left (11 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + 2 \, \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="giac")

[Out]

1/30000*sqrt(5)*(2*(4*(40*x - 59)*(5*x + 3) + 1293)*sqrt(5*x + 3)*sqrt(-10*x + 5) + 4785*sqrt(2)*arcsin(1/11*s
qrt(22)*sqrt(5*x + 3))) - 1/500*sqrt(5)*(2*(20*x - 23)*sqrt(5*x + 3)*sqrt(-10*x + 5) - 143*sqrt(2)*arcsin(1/11
*sqrt(22)*sqrt(5*x + 3))) + 1/50*sqrt(5)*(11*sqrt(2)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)) + 2*sqrt(5*x + 3)*sqr
t(-10*x + 5))

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maple [A]  time = 0.01, size = 88, normalized size = 0.94 \begin {gather*} \frac {1331 \sqrt {\left (-2 x +1\right ) \left (5 x +3\right )}\, \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )}{4000 \sqrt {5 x +3}\, \sqrt {-2 x +1}}+\frac {\left (-2 x +1\right )^{\frac {5}{2}} \sqrt {5 x +3}}{15}+\frac {11 \left (-2 x +1\right )^{\frac {3}{2}} \sqrt {5 x +3}}{60}+\frac {121 \sqrt {-2 x +1}\, \sqrt {5 x +3}}{200} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)/(5*x+3)^(1/2),x)

[Out]

1/15*(-2*x+1)^(5/2)*(5*x+3)^(1/2)+11/60*(-2*x+1)^(3/2)*(5*x+3)^(1/2)+121/200*(-2*x+1)^(1/2)*(5*x+3)^(1/2)+1331
/4000*((-2*x+1)*(5*x+3))^(1/2)/(5*x+3)^(1/2)/(-2*x+1)^(1/2)*10^(1/2)*arcsin(20/11*x+1/11)

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maxima [A]  time = 1.41, size = 58, normalized size = 0.62 \begin {gather*} \frac {4}{15} \, \sqrt {-10 \, x^{2} - x + 3} x^{2} - \frac {19}{30} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {1331}{4000} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) + \frac {171}{200} \, \sqrt {-10 \, x^{2} - x + 3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="maxima")

[Out]

4/15*sqrt(-10*x^2 - x + 3)*x^2 - 19/30*sqrt(-10*x^2 - x + 3)*x - 1331/4000*sqrt(10)*arcsin(-20/11*x - 1/11) +
171/200*sqrt(-10*x^2 - x + 3)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (1-2\,x\right )}^{5/2}}{\sqrt {5\,x+3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - 2*x)^(5/2)/(5*x + 3)^(1/2),x)

[Out]

int((1 - 2*x)^(5/2)/(5*x + 3)^(1/2), x)

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sympy [A]  time = 5.89, size = 230, normalized size = 2.45 \begin {gather*} \begin {cases} \frac {8 i \left (x + \frac {3}{5}\right )^{\frac {7}{2}}}{3 \sqrt {10 x - 5}} - \frac {187 i \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{15 \sqrt {10 x - 5}} + \frac {7139 i \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{300 \sqrt {10 x - 5}} - \frac {14641 i \sqrt {x + \frac {3}{5}}}{1000 \sqrt {10 x - 5}} - \frac {1331 \sqrt {10} i \operatorname {acosh}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{2000} & \text {for}\: \frac {10 \left |{x + \frac {3}{5}}\right |}{11} > 1 \\\frac {1331 \sqrt {10} \operatorname {asin}{\left (\frac {\sqrt {110} \sqrt {x + \frac {3}{5}}}{11} \right )}}{2000} - \frac {8 \left (x + \frac {3}{5}\right )^{\frac {7}{2}}}{3 \sqrt {5 - 10 x}} + \frac {187 \left (x + \frac {3}{5}\right )^{\frac {5}{2}}}{15 \sqrt {5 - 10 x}} - \frac {7139 \left (x + \frac {3}{5}\right )^{\frac {3}{2}}}{300 \sqrt {5 - 10 x}} + \frac {14641 \sqrt {x + \frac {3}{5}}}{1000 \sqrt {5 - 10 x}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)/(3+5*x)**(1/2),x)

[Out]

Piecewise((8*I*(x + 3/5)**(7/2)/(3*sqrt(10*x - 5)) - 187*I*(x + 3/5)**(5/2)/(15*sqrt(10*x - 5)) + 7139*I*(x +
3/5)**(3/2)/(300*sqrt(10*x - 5)) - 14641*I*sqrt(x + 3/5)/(1000*sqrt(10*x - 5)) - 1331*sqrt(10)*I*acosh(sqrt(11
0)*sqrt(x + 3/5)/11)/2000, 10*Abs(x + 3/5)/11 > 1), (1331*sqrt(10)*asin(sqrt(110)*sqrt(x + 3/5)/11)/2000 - 8*(
x + 3/5)**(7/2)/(3*sqrt(5 - 10*x)) + 187*(x + 3/5)**(5/2)/(15*sqrt(5 - 10*x)) - 7139*(x + 3/5)**(3/2)/(300*sqr
t(5 - 10*x)) + 14641*sqrt(x + 3/5)/(1000*sqrt(5 - 10*x)), True))

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